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315+3x^2-62x=0
a = 3; b = -62; c = +315;
Δ = b2-4ac
Δ = -622-4·3·315
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-8}{2*3}=\frac{54}{6} =9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+8}{2*3}=\frac{70}{6} =11+2/3 $
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